When a person cycled at 10 km per hour he arrived at his

When a person cycled at 10 km per hour he arrived at his office 6 minutes late. He arrived 6 minutes early, when he increased his speed by 2 km per hour. The distance of his office from the starting place is

Let the distance be x km.

∴	x	−	x	=	12
	10		12		60

⇒	6x − 5x	=	1
	60		5

⇒ x =	1	× 60 = 12 km
	5

Second Methdod :
Here, S₁ = 10, t₁ = 6
S₂ = 12, t₂ = 6

Distance =	(S₁ ×S₂)(t₁ + t₂)
	S₂ −S₁

=	(10 × 12)(6 + 6)
	12 − 10

=	120 × 12
	2

= 60 ×	12	km = 12 km
	60