A train leaves a station A at 7 am and reaches another station

A train leaves a station A at 7 am and reaches another station B at 11 am. Another train leaves B at 8 am and reaches A at 11.30 am. The two trains cross one another at

Let both trains meet after t hours since 7 a.m.
Distance between stations A and B = x Km.

∴	x	× t +	x	× (t − 1) = x
	4		7/2

	Speed =	Distance
		Time

⇒	t	+	2(t − 1)	= 1
	4		7

⇒	7t + 8t − 8	= 1
	28

⇒ 15 t – 8 = 28
⇒ 15 t = 28 + 8 = 36

⇒ t =	36	=	12	hours
	15		5

= 2 hours 24 minutes
∴ Required time = 9 :24 a.m.