A man walks a certain distance and rides back in 4 hours

A man walks a certain distance and rides back in 4 hours 30 minutes. He could ride both
ways in 3 hours. The time required by the man to walk both ways is

Suppose, time taken while walking be x hours
And, time taken on riding be y hours
∴ According to question

x + y = 4	1	hours ...(i)
	2

Then, 2y = 3 hours

y = 1	1	hours
	2

From equation (i)

x = 4	1	− 1	1	= 3 hours
	2		2

Time required to walk both ways = 6 hours