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A walks at a uniform rate of 4 km an hour; and 4 hours after his start, B bicycles after him at the uniform rate of 10 km an hour. How far from the starting point will B catch A ?
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- 16.7 km
- 18.6 km
- 21.5 km
- 26.7 km
Correct Option: D
Distance covered by A in 4 hours = 4 × 4 = 16 km
Relative speed of B with respect to A = 10 – 4 = 6 km/hr
∴ Time taken to catch A
= | = | hours | ||
6 | 3 |
∴ Required distance = | × 10 = | ||
3 | 3 |
= 26.67 km. ≈ 26.7 km