From two places, 60 km apart, A and B start towards each

From two places, 60 km apart, A and B start towards each other at the same time and meet each other after 6 hours.
Had A travelled with 2 of his speed
3
and B travelled with double of his speed, they would have met after 5 hours. The speed of A is

Let the speed of A = x kmph and that of B = y kmph
According to the question,
x × 6 + y × 6 = 60
⇒ x + y = 10 ....(i)

and,	2	x × 5 + 2y × 5 = 60
	3

⇒ 10x + 30y = 180
⇒ x + 3y = 18 ...(ii)
From equations (i) × (3) – (ii)
3x + 3y – x – 3y = 30 – 18
⇒ 12x = 12
⇒ x = 6 kmph.

Had A travelled with	2	of his speed
	3