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Ravi and Ajay start simultaneously from a place A towards B, 60 km apart. Ravi’s speed is 4 km/hr less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a place 12 km away from B. Ravi’s speed is
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- 12 km/hr
- 10 km/hr
- 8 km/hr
- 6 km/hr
Correct Option: C
Let the speed of Ravi be x kmph
then, Ajay’s speed = (x + 4) kmph
Distance covered by Ajay
= 60 + 12 = 72 km
Distance covered by Ravi
= 60 – 12 = 48 km.
According to the question,
| = | ||
| x + 4 | x |
| ⇒ | = | ||
| x + 4 | x |
⇒ 3x = 2x + 8
⇒ x = 8 kmph
