Three numbers are in the ratio 5:7:12. If the sum of the

Three numbers are in the ratio 5:7:12. If the sum of the first and the third numbers is greater than the second number by 50. The sum of the three numbers is

Let the numbers be 5x, 7x and 12x.
According to the question,
5x + 12x = 7x + 50
⇒ 17x – 7x = 50
⇒ 10x = 50

⇒ x =	50	= 5
	10

∴ Required sum
= 5x + 7x + 12x = 24x
= 24 × 5 = 120