A jar contained a mixture of two liquids A and B in the

A jar contained a mixture of two liquids A and B in the ratio 4 : 1. When 10 litres of the mixture was taken out and 10 litres of liquid B was poured into the jar, this ratio became 2 : 3. The quantity of liquid A contained in the jar initially was

Let the initial quantity of liquids A and B in the jar be 4x and x litres respectively.
After taking out 10 litres of the mixture,
Liquid A

= 4x –	4	× 10 = (4x – 8) litres
	5

Liquid B

= 4x –	1	× 10 = (4x – 2) litres
	5

After pouring 10 litres of liquid B,

4x − 8	=	2
4x – 2 + 10	=	3

⇒ 12x – 24 = 8x + 16
⇒ 4x = 40

⇒ x =	40	= 10
	4

∴ Quantity of liquid A = 4x
= 4 × 10 = 40 litres