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60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is
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- 53 kg
- 44 kg
- 80 kg
- 24 kg
Correct Option: B
In 60 kg of alloy A,
Lead = | × 60 = 36 kg. | |
5 |
Tin = | × 60 = 24 kg. | |
5 |
In 100 kg of alloy B,
Tin = | × 100 = 20 kg. | |
5 |
In 160 kg of new alloy,
Tin = 24 + 20 = 44 kg.