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  1. If ‘n’ be any natural number, then by which largest number (n3 – n) is always divisible ?
    1. 3
    2. 6
    3. 12
    4. 18
Correct Option: B

n3 – n = n (n2 – 1)
n3 – n = n (n + 1) (n – 1)
For n = 2, n3 – n
⇒ 23 – 2 = 8 - 2 = 6
Hence , ( n3 – n ) is divisible by 6.


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