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The sum of all natural numbers between 100 and 200, which are multiples of 3 is :
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- 5000
- 4950
- 4980
- 4900
Correct Option: B
Numbers divisible by 3 and lying between 100 and 200 are : 102, 105, 108, 111,...................... 198
Let number of terms = n
As we know the formula
an = a + ( n – 1 )d
where an = Nth Term a = First term , n = Number of terms and d = Common Difference
∴ 198 = 102 + ( n – 1 ) 3
⇒ n − 1 = | = 32 | |
3 |
⇒ n = 33
∴ Sn = | = ( First term + Last term ) | |
2 |
∴ Sn = | = ( a + l ) | |
2 |
∴ Sn = | (102 + 198) = 4950 | |
2 |