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  1. The sum of all natural numbers between 100 and 200, which are multiples of 3 is :
    1. 5000
    2. 4950
    3. 4980
    4. 4900
Correct Option: B

Numbers divisible by 3 and lying between 100 and 200 are : 102, 105, 108, 111,...................... 198
Let number of terms = n
As we know the formula
an = a + ( n – 1 )d
where an = Nth Term a = First term , n = Number of terms and d = Common Difference
∴  198 = 102 + ( n – 1 ) 3

⇒ n − 1 =
198 − 102
= 32
3

⇒  n = 33
∴  Sn =
Number of terms
= ( First term + Last term )
2

∴  Sn =
n
= ( a + l )
2

∴  Sn =
32
(102 + 198) = 4950
2



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