Find three consecutive numbers such that twice the first,

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Find three consecutive numbers such that twice the first, three times the second and four times the third together make 191.

Numbers = x, x +1 and x + 2
∴ 2x + 3x + 3 + 4x + 8 = 191
⇒ 9x = 191 – 11 = 180
⇒ x = 20
∴ Numbers = 20, 21 and 22