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A certain number on being divided successively by 9, 11 and 13 leaves remainder 8, 9 and 8 respectively. What are the remainders when the same number be divided by reversing the order of divisors?
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- 10, 1, 6
- 10, 6, 2
- 10, 3, 3
- 9, 3, 2
Correct Option: A
We proceed to find the number that is least as mentioned below.
x = 13 × 1 + 8 = 21
y = 11x + 9 = 11 × 21 + 9 = 231 + 9 = 240
z = 9y + 8 = 9 × 240 = 8 = 2160 + 8 = 2168.
Now, divide 2168 by 13, 11 and 9.
Hence, the remainders are 10, 1 and 6 respectively.
Remark : To determine the least number, we have taken the last quotient as 1.
