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The time in which ₹ 80,000 amounts to ₹ 92,610 at 10% p.a. compound interest, interest being compounded semi annually is :
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1 1 years 2 - 2 years
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2 1 years 2 - 3 years
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Correct Option: A
Given Here , Amount ( A ) = ₹ 92,610 , P = ₹ 80,000 , Rate ( R ) = 10% p.a. , Time = t half year and R = 5% per half year
| ∴ A = P | ![]() | 1 + | ![]() | T | |
| 100 |
| ⇒ 92,610 = 80,000 | ![]() | 1 + | ![]() | T | |
| 100 |
| ⇒ | = | ![]() | 1 + | ![]() | T | ||
| 80000 | 100 |
| ⇒ | = | ![]() | ![]() | T | ||
| 8000 | 20 |
| ⇒ | ![]() | ![]() | 3 | = | ![]() | ![]() | T | ||
| 20 | 20 |
| ⇒ T = 3 half years or 1 | years | |
| 2 |

