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On a certain principal the compound interest compounded annually for the second year at 10% per annum is ₹ 132. The principal is
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- ₹ 1250
- ₹ 1000
- ₹ 1200
- ₹ 1320
Correct Option: C
Let principal be Rs. P.
Here , Compound Interest ( CI ) = ₹ 132 , P = ? , Rate ( R ) = 10% , Time = 2 years
| Interest in 1 year = | |
| 100 |
| Interest in 1 year = | = ₹ | ||
| 100 | 10 |
According to question,
| ∴ P | ![]() | ![]() | 1 + | ![]() | 2 | − 1 | ![]() | − | = 132 | ||
| 100 | 10 |
| ⇒ P | ![]() | ![]() | 1 + | ![]() | 2 | − 1 | ![]() | − | = 132 | ||
| 100 | 10 |
| ⇒ P | ![]() | ![]() | ![]() | 2 | − 1 | ![]() | − | = 132 | ||
| 10 | 10 |
| ⇒ P | ![]() | − 1 | ![]() | - | = 132 | ||
| 100 | 10 |
| ⇒ P | ![]() | ![]() | - | = 132 | |||
| 100 | 10 |
| ⇒ | − | = 132 | ||
| 100 | 10 |
| ⇒ | = 132 | |
| 100 |
| ⇒ | = 132 | |
| 100 |
| ⇒ P = | = ₹ 1200 | |
| 11 |



