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If a = 1 (a > 0), then the value of a + 1 is a − 5 a
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- √29
- −√27
- −√29
- √27
Correct Option: A
| a = | |
| a – 5 |
⇒ a2 – 5a = 1
⇒ a2 – 5a – 1 = 0
| ∴ a = | |
| 2 |
![]() | If ax² + bx + c = 0, then x = | ![]() | |
| 2a |
| = | |
| 2 |
| = | |
| 2 |
| If a = | , then | |
| 2 |
| = | ||
| a | 5 + √29 |
| × | ||
| 5 + √29 | 5 − √29 |
| = | = | ||
| 25 − 29 | −2 |
| ∴ a + | = | − | |||
| a | 2 | 2 |
| = | = √29 | |
| 2 |

