-
If (2a – 3)2 + (3b + 4)2 + (6c + 1)2 = 0, then the value of
a3 + b3 + c3 − 3ac + 3 is : a2 + b2 + c2
-
- abc + 3
- 6
- 0
- 3
Correct Option: D
(2a – 3)2 + (3b + 4)2 + (6c + 1)2 = 0
| ∴ 2a – 3 = 0 ⇒ a = | , | |
| 2 |
| 3b + 4 = 0 ⇒ b = | |
| 3 |
| 6c + 1 = 0 ⇒ c = – | |
| 6 |
| ∴ a + b + c = | – | – | |||
| 2 | 3 | 6 |
| = | = 0 | |
| 6 |
∴ a3 + b3 + c3 − 3ac = 0
| ∴ | + 3 | |
| a2 + b2 + c2 |
= 0 + 3 = 3
