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If for a non–zero x, 3x2 + 5x + 3 = 0, then the value of x3 + 1 is : x3
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10 27 -
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10 
27 -
2 3 -
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2 
3
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Correct Option: A
3x2 + 5x + 3 = 0
⇒ 3x2 + 3 = –5x
| ⇒ | = –5 | |
| x |
| ⇒ 3x + | = –5 | |
| x |
| ⇒ x + | = – | ||
| x | 3 |
On cubing both sides,
![]() | x + | ![]() | 3 | = | ![]() | ![]() | 3 | = | |||
| x | 3 | 27 |
| ⇒ x3 + | + 3 | ![]() | x + | ![]() | = | |||
| x3 | x | 27 |
| ⇒ x3 + | + 3 × | = | |||
| x3 | 3 | 27 |
| ⇒ x3 + | = | + 5 | ||
| x3 | 27 |
| = | = | ||
| 27 | 27 |