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A and B can do a work in 45 days and 40 days respectively. They began the work together but A left after some time and B completed the remaining work in 23 days. After how many days of the start of the work did A leave ?
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- 10 days
- 9 days
- 8 days
- 5 days
Correct Option: B
(A + B)’s 1 day’s work
| = | ![]() | + | ![]() | = | 45 | 40 | 360 |
Work done by B in 23 days
| = | × 23 = | |||
| 40 | 40 |
| Remaining work = 1 - | = | |||
| 40 | 40 |
| Now | work was done by (A + B) in 1 day | 360 |
| ∴ | work was done by | 40 |
| (A + B) in 1 × | × | = 9 days. | ||
| 17 | 40 |
Hence, A left after 9 days.
Aliter : Using Rule 26,
Here, x = 45, y = 40, a = 23
| ⇒ Required time t = | × x | (x + y) |
| t = | (45 + 40) |
| = | = 9 days | 85 |

