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A and B together can complete a job in 8 days. Both B and C, working alone can finish the same job in 12 days. A and B commence work on the job, and work for 4 days, where upon A leaves. B continues for 2 more days, and then he leaves too. C now starts working, and finishes the job. How many days did C require ?
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- 5
- 8
- 3
- 4
Correct Option: D
Work done by A and B in first 6 days
= (A + B)’s 4 days’ work + B’s 2 days’ work
| = 4 × | + | |||
| 8 | 12 |
| = | + | |||
| 2 | 6 |
| = | = | = | ||||
| 6 | 6 | 3 |
Remaining work
| = 1 - | = | |||
| 3 | 3 |
∴ Time taken by C
| = | × 12 = 4 days. | 3 |
