A candidate who scores 30 percent fails by 5 marks, while

A candidate who scores 30 percent fails by 5 marks, while another candidate who scores 40 per cent marks gets 10 more than minimum pass marks. The minimum marks required to pass are

Let the full marks in that examination were x.
According to the question,

=	30x	+ 5 =	40x	- 10
	100		100

=	3x	-	4x	= 10 + 5
	10		10

⇒	x	= 15
	10

∴ x = 150
∴ Minimum pass marks

⇒	30	× 150 + 5 = 50
	100

Aliter : Using Rule 22,
m = 30%, n = 40%,
p = 5, q = 10.
Maximum marks

=	100	× (p + q)
	(n - m)

=	100	× (5 + 10) = 150
	(40 - 30)

∴ Minimum passing marks

= 150 ×	30	+ 5 = 45 + 5 = 50
	100