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Two students appeared for an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. The marks obtained by them are
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- 40 and 31
- 72 and 63
- 42 and 33
- 68 and 59
Correct Option: C
Let marks obtained by the first student be x.
∴ Marks obtained by the second
student = x – 9
According to the question,
x = 56% of (x + x – 9)
⇒ x = | 100 |
⇒ 100x = 112x – 504
⇒ 112x – 100x = 504
⇒ 12x = 504
⇒ x = | = 42 | 12 |
∴ Marks obtained by the second student = 42 – 9 = 33