-
What is the 507th term of the sequence 1, –1, 2, –2, 1, –1, 2, – 2, 1, ....?
-
- –1
- 1
- –2
- 2
- –1
Correct Option: D
On the basis of above given series ,
Clearly, repetition takes place for each set of four terms.
Hence, 507th term will be 2507, when divided by 4, gives 3 as remainder and 3rd term is 2. Thus , option D is correct answer.
