The 30th term of the series 30, 251, 21 , 161,........ is22

Here , First term = a = 30

Common difference (d) = 25	1	- 30 = - 4	1	=	- 9
	2		2		2

Number of terms = n = 30
∴ T_n = a + (n – 1)d

⇒ T₃₀ = 30 + (30 – 1) ×	-9
	2

T₃₀ = 30 -	29 × 9
	2

T₃₀ = 30 -	261
	2

T₃₀ =	60 - 261
	2

T₃₀ =	- 201	= -100	1
	2		2

- 100	1
	2

- 133	1
	2