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ABC is an isosceles triangle with AB = AC. A circle through B touching AC at the middle point intersects AB at P. Then AP : AB is :
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- 4 : 1
- 2 : 3
- 3 : 5
- 1 : 4
- 4 : 1
Correct Option: D
On the basis of given in question , we draw a figure of an isosceles triangle ABC ,
Let AB = AC = 2y
⇒ AQ = QC = y
∵ AB is a secant.
⇒ AP × AB = AQ²
⇒ AP × 2y = y²
| ⇒ AP = | ||
| 2 |
| ∴ | = | = | or 1 : 4 | |||
| AB | 2 × 2y | 4 |
