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If in a triangle ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and AD / BD = 3 / 5 . If AC = 4 cm, then AE is
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- 1.5 cm
- 2.0 cm
- 1.8 cm
- 2.4 cm
- 1.5 cm
Correct Option: A
As per the given in question , we draw a figure of triangle ABC in which D and E are on the sides AB and AC, such that, DE is parallel to BC ,
DE || BC ,
| ∴ | = | |||
| AB | AC |
| = | ⇒ | = | ||||||
| BD | 5 | AD | 3 |
| ⇒ | + 1 = | + 1 | |||
| AD | 3 |
| ⇒ | = | |||
| AD | 3 |
| ⇒ | = | |||
| AD | 3 |
| ⇒ | = | |||
| AB | 8 |
| ∴ | = | |||
| AB | AC |
| ⇒ | = | ⇒ AE = | ||||
| 8 | 4 | 8 |
AE = 1.5 cm.
