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The side BC of ∆ ABC is extended to the point D. If ∠ACD = 112° and ∠B = 3/4 ∠A, then the value of ∠B is
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- 64°
- 48°
- 46°
- 50°
- 64°
Correct Option: B
As per the given in question , we draw a figure triangle ABC whose side BC is extended to the point D 
∵ Exterior angle of triangle is equal to the sum of two opposite angles.
∵ ∠ACD = 112°
∴ ∠A + ∠B = 112°
| ⇒ | ∠B + ∠B = 112° | |
| 3 |
| ⇒ | = 112° | |
| 3 |
 | ∵ ∠B = | ∠A ⇒ ∠A = | ∠B |  | ||
| 4 | 3 |
⇒ 7 × ∠B = 112 × 3
| ⇒ ∠B = | = 48° | |
| 7 |
