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D and E are the points on the sides AB and AC respectively of a ∆ ABC and AD = 8 cm, DB = 12 cm, AE = 6 cm and EC = 9 cm, then BC is equal to :
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2 DE 5 -
5 DE 2 -
3 DE 2 -
2 DE 3
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Correct Option: B
As per the given in question , we draw a figure triangle ABC whose D and E are the points on the sides AB and AC respectively 
Here , AD = 8 cm, DB = 12 cm, AE = 6 cm and EC = 9 cm
According to the question,
| = | = | ||||
| DB | 12 | 3 |
| = | = | ||||
| EC | 9 | 3 |
| ∴ | = | = | |||
| DB | EC | 3 |
| ⇒ | = | = | |||
| AD | AE | 2 |
| ⇒ | = | = | |||
| AD | 2 | AE |
| ⇒ | = | = | |||
| AD | 2 | AE |
∴ ∆ ABC ~ ∆ ADE
| ∴ | = | = | |||
| AD | DE | 2 |
| ⇒ BC = | DE | |
| 2 |