In a circle with centre O, AB and CD are two diameters perpendicular

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In a circle with centre O, AB and CD are two diameters perpendicular to each other. The length of chord AC is

On the basis of question we draw a figure of a circle with centre O ,

Radius = OA = OB = OC =	AB
	2

∴ AC = √OA² + OC²
From ∆ AOC

AC = √		AB		²	+		AB		²
		2					2

AC = √	AB² + AB²
	4

AC = √	AB²
	2

AC =	AB
	√2