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Three pipes 1, 2 and 3 together take 24 hours to fill a tank. The three pipes are opened for 6 hours after which Pipe 3 is closed. Pipe 1 and 2 take another 30 hours to fill the tank. In how much time would Pipe 3, alone fill the tank?
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- 40 hours
- 30 hours
- 68 hours
- None of these
- 40 hours
Correct Option: D
According to question ,
| Tank filled by all 3 in 6 hours = |  |  | 6 = | ||
| 24 | 4 |
| Remaining = | | 1 - | | = | is filled by, Pipe 1 and 2 in 30 hours | ||
| 4 | 4 |
| So, the entire tank would be filled by 1 and 2 in 40 hours 1 hour work of all 3 = | ||
| 24 |
| 1 hour work of Pipe 1 & 2 = | ||
| 40 |
| Hence, 1 hour work of Pipe 3 = | - | = | = | ||||
| 24 | 40 | 120 | 60 |
∴ Pipe 3 alone would fill the tank in 60 hours.
