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  1. In ∆ABC, D and E are two points on the sides AB and AC respectively so that DE||BC and
    AD
    =
    2
    BD3

    Then
    the area of trapezium DECB
    is equal to
    the area of ∆ABC

    1. 5/9
    2. 21/25
    3. 1
      4
      5
    4. 5
      1
      4
Correct Option: B


DE || BC
∴ ∠ADE = ∠ABC
∠AED = ∠ACB
∴ ∆ADE ~ ∆ABC

AD
=
2
BD3

BD
=
3
AD2

=
BD
+ 1 =
3
+ 1
AD2

BD + AD
AD

3 + 2
AB
=
5
2AD2

Area of ∆ADE
=
AD²
=
2
² =
4
Area of ∆ABCAB²525

⇒ 1 -
Area of ∆ADE
= 1 -
4
Area of ∆ABC25

Area of ∆ABC - Area of ∆ADE
=
25 - 4
Area of ∆ABC25

Area of trapezium DECB
=
21
Area of ∆ABC25



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