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Let C1 and C2 be the inscribed and circumscribed circles of a triangle with sides 3cm, 4cm and 5cm then
area of C1 is area of C2
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- 9/25
- 4/25
- 9/16
- 16/25
- 9/25
Correct Option: B
Using Rule 1 and 14,
It is a right angled triangle. 
Radius of circum circle C2
= 5/2 cm. because
AC = Diameter of circle
| Semi-perimeter of ∆ABC(s) = | = 6cm. | |
| 2 |
| Area of ∆ABC = | × 3 × 4 = 6 sq.cm. | |
| 2 |
| ∴ In-radius = | = | = 1 cm. | ||
| s | 6 |
| ∴ | = | ||||||
| Area of C2 | π × |  |  | ² | |||
| 2 | |||||||
| = | ||
| 4 | ||
| = | |
| 25 |
