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Which of the following curves represents the function y = (|esinC( |x|)) for |x| < 2π ?
Here, x represents the abscissa and y repreents the ordinate.
Correct Option: C
f(x) = ln(| e[| sin(| x|)|]|)
1. |x| ⇒ f(x) is Even. Hence, option (b) is not possible
2. m =| sin(|x| )| > = 0 ⇒ em > = 1
3. ⇒f(x) = ln(|em|) = ln(em) >= 0 {from 2}
Hence, option (a) is not possible
4. and f(x)x=0 = 0
Hence, option (d) is not possible
Therefore, correct option is (c).
