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What is the equation of the line whose y-intercept is (–3/4) and making an angle of 45° with the positive x–axis?
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- 4x – 4y = 3
- 4x – 4y = –3
- 3x – 3y = 4
- 3x – 3y = –4
- 4x – 4y = 3
Correct Option: A
Slope of straight line = m = tanq = tan45° = 1
| Intercept on Y–axis = c = | |
| 4 |
∴ The required equation is : y = mx + c
| ⇒ y = 1.x – | |
| 4 |
⇒ 4y = 4x – 3
⇒ 4x – 4y = 3
