If p + 1 = 1 then the value of (p + 2)² + 1

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Given,

p +	1	= 1
	p + 2

⇒ (p + 2) +	1	= 2 + 1 = 3
	p + 2

On cubing both sides,

⇒ (p + 2)³ +	1	+ 3(p + 2) ×	1		p + 2 +	1		= 27
	(p + 2)³		p + 2			p + 2

⇒ (p + 2)³ +	1	+ 3 × 3 = 27
	(p + 2)³

⇒ (p + 2)³ +	1	= 27 - 9 = 18
	(p + 2)³

∴ (p + 2)³ +	1	- 3
	(p + 2)³

= 18 – 3 = 15

If p +	1	= 1 then the value of (p + 2)² +	1	- 3 is :
	p + 2		(p + 2)³