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The liquids, X and Y are mixed in the ratio of 3 : 2 and the mixture is sold at Rs. 11 per litre at a profit of 10%. If the liquid X costs Rs. 2 more per litre than Y, the cost of X per litre is (in Rs.) :
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- 10.80
- 11.75
- 9.50
- 11
Correct Option: A
Let 3 litres of liquid X and 2 litres of liquid Y be mixed together.
Let Cost of liquid Y = Rs. p /litre
Cost of liquid Y = Rs. (p + 2)/litre
According to the question,
Cost of the mixture = Rs. (3p + 6 + 2p) = Rs. (5p + 6)
| ∴ (5p + 6) × | = 11 × 5 | 100 |
| ∴ (5p + 6) = | = 50 | 11 |
⇒ 5p = 50 – 6 = 44
| ⇒ p = | = Rs. 8.8 | 5 |
∴ Cost of liquid X = p + 2 = 8.8 + 2 = Rs. 10.8/litre
