Correct Option: B
Given in question , Total price of two boxes = 1300
Let CP of one box = y
Then CP of other box = (1300 – y)
Profit on 1st box = 20%
∴ SP of 1st box = y + | 20 | y |
100 |
SP of 1st box = | | 100y + 20y | = Rs. | 120y | |
100 | 100 |
Loss on 2nd box = 12%
∴ SP of 2nd box = CP – Loss
SP of 2nd box = (1300 – y) – | 12 | (1300 – y) |
100 |
SP of 2nd box = (1300 - y) | | 1 - | 12 | | | |
100 |
SP of 2nd box = (1300 – y) × | 88 | |
100 |
SP of 2nd box = 1144 - | 88y | |
100 |
But SP of both boxes is same
⇒ | | 120y | = 1144 - | 88y | |
100 | 100 |
⇒ | | 120y | +
| 88y | = 1144 |
100 | 100 |
⇒ y = | 1144 × 100 | = 550 |
208 |
∴ Cost price of 1st box = $ 550
and cost price of another box = $ 1300 – $ 550 = $ 750