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A dealer sold two coolers at $ 2,970 each. On selling one cooler, he gained 10%, on selling the other he lost 10%. Find the dealer’s gain or loss per cent.
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- 1% loss
- 1% gain
- 2% loss
- 2% gain
Correct Option: A
Here , S P of one cooler = $ 2,970
Profit % = 10 %
Let C P of the cooler be p
Then, SP = CP + Profit
| ⇒ 2970 = p + | p | 100 |
| ⇒ 2970 = | p | 100 |
| ⇒ | × 100 = p | 110 |
⇒ p = $ 2700
For 2nd cooler, S P = $ 2970
Loss = 10 %
Let CP = q, then
SP = CP – Loss = 2970
| 2970 = q - | q | 100 |
| ⇒ | = 2970 ⇒ q = $ 3300 | 100 |
∴ Total cost price for coolers = $ 2700 + 3300 = $ 6000
Total selling price for two coolers = $ 2970 + 2970 = $ 5940
Hence, Loss = $ 6000 – 5940 = $ 60
| & Loss % = | × 100 = 1% | 6000 |
