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Find the sum of three numbers which are prime to one another such that the product of the first two is 437 and that of the last two is 551 ?
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- 91
- 81
- 71
- 70
Correct Option: C
From the question we see that the second number is a common factor of the two products and since the numbers are prime to one another. It is their . H. C. F . and is, therefore, 19.
∴ The first number = 437 / 19 = 23
and the third number = 551 / 19 = 29
Hence, the number are 23, 19 and 29
∴ Sum = 23 + 19 + 29
= 71.
