The total transmitted power given by the AM signalφAM(t)

The total transmitted power given by the AM signal
φ_AM(t) = 10 cos (2π × 10⁶t) + 5 cos(2π × 10⁶t)
cos (2π × 10³t) + 2 cos (2π × 10⁶t) + cos (4π × 10³t)

The given amplitude modulation equation is φ_AM (t) = 10 cos (2π × 10⁶t) + 5 cos (2π × 10⁶t) cos (2π × 10³t) + 2 cos (2π × 10⁶t) cos (4π × 10³t)

φ_AM (t) =		1+	5	cos(2π × 10³t)	+	2	cos(4π×10³t)
			10			10

where,

μ₁ =	5	= 0.5
	10

μ₂ =	2	= 0.2
	10

A_c = 10
Now, total transmitted power

P_t = P_c		1 +	μ_eff²
			2

μ_eff² = μ²₁+μ²₂ = 0.5²+0.2²
or
μ_eff² = 0.25 + 0.4 = 0.29
Now

P_t =	A²		1 +	0.29
	2			2

=	10²	×1.145 = 57.25 W
	2