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A television signal is sampled at a rate of 25% above the Nyquist rate. The signal has a bandwidth of 6 MHz. The samples are quantized into 512 levels. The minimum bandwidth required to transmit this signal would be—
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- 135M bits/sec
- 67.5 M bits/sec
- 270 M bits/sec
- None of these.
- 135M bits/sec
Correct Option: A
Given that fm = 6MHz
fs = 2fm + 25 % of 2fm
fs = 12MHz + | MHz | |
100 |
fs = 15MHz
and
L = 2n = 512
n = 9
BW = nfs = 15 × 9 MHz = 135 MHz