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A PCM system uses a uniform quantizer followed by a 8- bit encoder. The bit rate of the system is equal to 106bits/s. The maximum message bandwidth for which the system operates satisfactory is—
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- 25 MHz
- 6.25MHz
- 12.5 MHz
- 50 MHz
- 25 MHz
Correct Option: B
Let the message bandwidth ω Nyquist rate = 2ω
bandwidth = 2ω × (no. of bits/sec taken for quantization)
= 2ω × 8 = 16ω bits/sec
given that bit rate = 108 bits/sec
Now, 108 = 16ω
ω = | ×100 = 106 = 6.25 MHz | |
16 |