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A non-linear device with a transfer characteristic given by i = (0 + 2Vi + 0·2Vi2) mA is supplied with a carrier of 1V amplitude and a sinusoidal signal of 0.5V amplitude in series. If at the output the frequency component of AM signal is considered, the depth of modulation is—
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- 18%
- 10%
- 20%
- 33.33%
- 18%
Correct Option: B
Given transfer characteristic
i = (10 + 2Vi + 0·2 Vi2) mA …(A)
Since, according to question both carrier and sinusoidal signals are in series. Let assume Vi is represented as
Vi = Am cos ωmt + Ac cos ωct
or
Vi = 0·5 cos ωmt + cos ωct (˙.˙ Am = 0·5V, Ac = 1V)
Now, on putting the value of Vi in equation (A) we get amplitude modulated AM signal i.e.,
i = 10 + 2 (cos ωct + 0·5 cos ωmt) + 0·2 (cos ωct + 0·5 cos ωmt)2
or
i = 2 cos ωc t + 0·2 cos ωct + cos ωmt
(˙.˙ At the output only lower frequency terms are considered and neglecting the higher frequency terms)
i = 2 | 1 + | cos ωmt | cos ωct | ||||
2 |
which is equal to standard AM equation.
i = Ac (1 + μ cos ωmt) cos ωct …(C)
So, on comparing equation (B) and (C) we get
μ = | = 0.1 | |
2 |
and% modulation index = 0.1 x 100 = 10%.
Hence alternative (B) is the correct choice.