Correct Option: C

Given message signal
m(t) = 9 cos 20πt + 7 cos 60πt
|m(t )|_max = 9 + 7 = 16 at t = 0
Therefore, the power in normalized message signal

m(t) =	Power in the signal m(t)
	Max. power in signal m(t)

=	92/2 + 72/2	= 0.254
	(16)2