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An AM modulation has output xc(t) = A cos 400πt + B cos 380πt + B cos 400πt
The carrier power is 100 W and the efficiency is 40%. The value of A and B are—
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- 14.14, 16.33
- 50, 10
- 22.36,13.46
- None of these
Correct Option: A
Given modulator output
xc(t) = A cos 400 πt + B cos 380 πt + B cos 420 πt …(i)
Carrier power = 100 W
Efficiency = 40%
Equation (i) can be represented in standard equation as
xct = A | 1 + | cos 20 πt | cos 400 πt | |||
A |
Given that
Pc = 100 = | |
2 |
μ = | |
A |
A2 = 200
or
A = √200 = 14.14
Efficiency = | |
2 + μ2 |
0.4 = | |
2 +(B/A)2 |
or
0.4 = | |
2A2 + B2 |
or
0.8A2 + 0.4B2 = B2
or
B2 = | = | = | × 200 | = | ||||
0.6 | 3 | 3 | 3 |
or
B = | √ | = | √266.67 | = 16.33 | |
3 |