In an AM wave, the total power content is 600 W and that

In an AM wave, the total power content is 600 W and that of each sideband is 75 W. The modulation index is—

We know that

P_T = P_c		1 +	μ²
			2

P_T = P_c + P_c.	μ²
	2

Where,
P_T = Total Power
P_c = Carrier Power

P_c.	μ²
	2

= Power of both sideband
600 = P_c + 2 × 75
or
P_c = 600 - 150 = 450W
Now,

150 = P_c.	μ²
	2

150 = 450.	μ²
	2

μ² =	2
	3

μ =	√	2	= 0.816
		3

or
μ = 81.6 %