For 1 ≤ t ≤ 2 the phase deviation is

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For 1 ≤ t ≤ 2 the phase deviation is—

1. 500 πt rad
2. 250 π (1 + 2t) rad
3. 20 πt rad
4. 0

Correct Option: B

Phase deviation,
Δφ(t)=2πkf ∫^t₀ m(t)dt
for
0 ≤ t ≤ 1, Δφ(t)=2π·25 ∫^t₀ 10tdt = 250πt²
and
Δφ(1) = 250π
Now for 1 ≤ t ≤ 2, Δφ(t) = Δφ (1) + 2π·25 ∫^t₀ 10dt
= 250π + 500πt
= 250π (1 + 2t) rad
Hence alternative (B) is the correct choice.