-
The state and output equation of a system are as under state equation:

x1 (t) 
= 
0 1 

x1 (t) 
+ 
0 
u(t) x2 (t) -1 -2 x2 (t) 1
AndC(t) =[1 1] 
x1 (t) 
x2 (t)
The system is—
-
- neither state controllable nor output controllable
- state controllable but not output controllable
- output controllable but not state controllable
- both state controllable and output controllable
Correct Option: B
Given state equation:
![]() | ![]() | = | ![]() | ![]() | ![]() | ![]() | + | ![]() | ![]() | u(t) | |||||||
| x2 | (t) | -1 | -2 | x2 | (t) | 1 |
| C(t) = [1 1] | ![]() | ![]() | ||
| x2 | (t) |
Here,
| A = | ![]() | ![]() | ||
| -1 | -2 |
| B = | ![]() | ![]() | ||
| 1 |
C = [1 1]
Check for controllability
| AB = | ![]() | ![]() | ![]() | ![]() | = | ![]() | ![]() | |||||
| -1 | -2 | 1 | -2 |
∴ QC = [B: AB] = – 1, which is non-singular.
Hence, the state equation is controllable.
Check for observability :
| A = | ![]() | ![]() | ||
| -1 | -2 |
then
| AT = | ![]() | ![]() | ||
| 1 | -2 |
C = [1 1]
then
| CT = | ![]() | ![]() | |
| 1 |
Now,
| ATCT = | ![]() | ![]() | ![]() | ![]() | |||
| 1 | -2 | 1 |
| = | ![]() | ![]() | |
| -1 |
θ0 = [CT : AT CT]
| ATCT = | ![]() | ![]() | ||
| 1 | -1 |
= 0 i.e., singular.
Hence given system equation is not observable.
Therefore alternative (B) is the correct choice.