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Assume the diodes are ideal, calculate the value of I and V for the circuit shown below:
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- 2 mA, 0 V
- 0 mA, 3.3 V
- 2 mA, 3.3 V
- None of these
Correct Option: B
Again here let us assume that both diodes are conducting.
Then VA = 0 and V = 0, the current in Diode D2 can be calculated as:
| ID2 = | 2 mA. | |
| 5 |
KCL at node A.
| I + 2 = | |
| 10 |
I = – 1 mA → which is not possible.
It means our original assumption is not correct. We start again, assuming that D1 is off and D2 is on
| The current ID2 = | 1.33 mA. | |
| 15 |
VA = – 10 + 10 × 1.33 = + 3.3 V
As we assumed that diode D1 is reversed biased it means
I = 0.
Hence alternative (B) is the correct choice.
