Direction: Consider the circuit Assume diodes are ideal.
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If V1 = – 5 V and V2 = 5 V then V 0 is:
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- 9.474 V
- 8.943 V
- 4.5 V
- 9 V
Correct Option: C
Since given V1 = – 5 V and V2 = 5 V, so we assume that D1 is OFF and D2 is ON
| V0 = | = | = 4.5 V | ||
| 9 + 1 | 10 |
Check assumption
| ID1 = | = | |||
| 1 kΩ | 1 kΩ |
= 0.5 mA > 0, therefore D2 is ON
VD1 = V1 – V0 = – 5 – 4.5
= – 9.5 < 0, therefore D1 is OFF Hence alternative (C) is the correct choice.
